STAR - Another one

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STAR - Another one

Post  SwitchCase on Wed Aug 13, 2008 10:11 am

This is a snippet

for(double r=0.0;r!=1.0;r+=0.1)printf("*");



How many * will be printed.
And Why???

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Re: STAR - Another one

Post  Rahul Agrawal on Wed Aug 13, 2008 11:11 am

check out this......
u will understand....

float a=3.4;
float b=3.5;
if(a==3.4)
cout<<"hi1";
else
cout<<"bye1";
if(b==3.5)
cout<<"hi2";
else
cout<<"bye2";

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Re: STAR - Another one

Post  Rahul Agrawal on Wed Aug 13, 2008 11:12 am

ohh..ans of ur que is infinite..........

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@rahul

Post  mnnit.rahul on Wed Aug 13, 2008 11:27 am

infinite to hai but kyu???
are hum use 0.1 time increase kr rahe hai usme kuch panga hai
because even after becoming 1 r !=1.0 but if we increase r by 1 then it works fine

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Re: STAR - Another one

Post  shivang on Wed Aug 13, 2008 1:20 pm

Floating-point decimal values generally do not have an exact binary representation. This is a side effect of how the CPU represents floating point data. Different compilers and CPU architectures store temporary results at different precisions, so results will differ depending on the details of your environment. If you do a calculation and then compare the results against some expected value it is highly unlikely that you will get exactly the result you intended.
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@shivang

Post  mnnit.rahul on Thu Aug 14, 2008 2:13 am

if this is the case the
double t=1.0
if(t==1.0)
cout<<"yes";
else
cout<<"no";
this should gi\ve the answer NO
but instead it i giving YES
moreover if we increase the duoblevalue by 1 it works fine but problem came when we increase it by 0.1

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