HOW MANY *'s

#include<stdio.h>
int main()
{
short i=0;
short n=42;

for( i=0;i<n;n++)
printf("*");

}


CAN U TELL THE NO OF STARS THAT WILL BE PRINTED?

if max no. than "n" can hold is x then after x it become -(x+1)
so ans should be (x-42)+x+1 as n start from 42 so it reaches to max val x then become -(x+1) then again increase and reaches to 0

32726 times
range of short int in gcc -32768 to 32767
now n=42 and * will be printed at n=32767 are (32767-42+1=) 32726
now at next iteration n=-32768 which is less than i(which is equal to zero) ,hence the loop break
@etawah it's (x-42)+1

abe limit nahi yaad thi
so i used x instead of 32767
samajh gaya!!!!!